Blog · November 4, 2026

How far away can a security camera recognize a face? 4.3 m, worked out from the pixels

Home › Blog › How far away can a security camera recognize a face? 4.3 m, worked out from the pixels

A camera spec sheet gives a resolution and a lens angle, and it is tempting to read “4 megapixels” as “good enough to see a face”. But what matters is how many pixels land on the thing you care about, and that falls as the subject moves away. A little trigonometry gives you the distance at which each job stops being possible, so you can decide where to mount a camera before you drill a hole.

What the jobs need

The standard for video surveillance (IEC 62676-4) names four levels, by pixels per meter across the subject:

The method

The camera sees a triangle. At distance d, the width of the view is

width = 2 × d × tan(field of view ÷ 2)

and the pixel density is the camera’s horizontal pixels divided by that width. Turn it around to find the distance for a given density:

d = pixels ÷ (2 × density × tan(field of view ÷ 2))

Worked example: a 4 MP camera

The camera is 2,560 pixels wide behind a 2.8 mm lens with a 100° field of view. Half the angle is 50°, and tan 50° = 1.1918.

A 4 megapixel camera with a 100 degree lens identifies a face to 4.30 metres, recognizes to 8.59, observes to 17.18 and detects to 42.96. How far a 4 MP camera at 100° can do each job Identify (250 px/m) 4.3 m Recognize (125 px/m) 8.59 m Observe (62.5 px/m) 17.18 m Detect (25 px/m) 42.96 m 2,560 px across, a 2.8 mm lens: the further the subject, the fewer pixels on it
A 4 megapixel camera with a 100° lens identifies to 4.30 m, recognizes to 8.59 m, observes to 17.18 m and detects to 42.96 m.

Check the first one: at 4.30 m the view is 2 × 4.30 × 1.1918 = 10.24 m wide, and 2,560 ÷ 10.24 = 250 px/m.

Worked example: a doorbell camera

A doorbell camera has 1,920 pixels across and a 140° field of view. Half the angle is 70°, and tan 70° = 2.7475. A caller standing 1.0 m away is in a view 2 × 1.0 × 2.7475 = 5.495 m wide, so the density is 1,920 ÷ 5.495 = 349.4 px/m. To keep the 250 px/m needed to identify, d = 1,920 ÷ (2 × 250 × 2.7475) = 1.40 m.

At one meter a doorbell camera with 1920 pixels and a 140 degree lens gives 349.4 pixels per meter, a 2560 pixel 100 degree camera gives 1074. Same math, two cameras Pixels per meter on a person 1 m away Doorbell, 1,920 px, 140° 349.4 px/m Hallway camera, 2,560 px, 100° 1,074 px/m Identify needs 250 px/m: doorbell out to 1.40 m, hallway camera to 4.30 m. A wide lens spreads the same pixels over a bigger scene.
At 1 m, a 140° doorbell with 1,920 pixels gives 349.4 px/m and a 100° camera with 2,560 pixels gives 1,074 px/m. The doorbell identifies to 1.40 m, the other camera to 4.30 m.

A wide lens is good for seeing a whole porch. It is poor for identifying someone standing at the far end of it.

Honest limits

Datasheet “DORI” distances for wide lenses often run about 30% longer than this formula gives, so treat them as a best case and compute your own. The numbers also assume the subject faces the camera in good light. At night, or at an angle, plan for a shorter reach.

Check it yourself

Stand a friend at the distance, record, and count the pixels across their face on a still. 40 pixels or more across a 16 cm face is identify.

Try it with your own camera

The free Pixels per Meter calculator takes your camera’s horizontal pixels and field of view and gives the reach for each level, or the density at a distance you choose. It comes from Every Angle, which measures a home, plans its cameras and lights with geometry, algebra and trigonometry, and shows how to check any quote or install the kit yourself. It is available as a hardcover.

every-angle cover
Every AngleSee the chapters, free calculators and printable sheets.

Camera specifications above are typical examples. Check your own camera’s datasheet and test it.

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